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adventofcode/2025/day11/solve.py
2025-12-11 09:44:39 +01:00

71 lines
1.6 KiB
Python
Executable File

#!/usr/bin/env python3
from collections import defaultdict
import fileinput
from typing import Iterable
import networkx as nx
def parse_graph() -> nx.Graph:
graph = nx.DiGraph()
for line in fileinput.input():
source, rem = line.split(": ")
for sink in rem.strip().split(" "):
graph.add_edge(source, sink)
return graph
def count(gen: Iterable) -> int:
return sum(1 for _ in gen)
def main() -> None:
graph = parse_graph()
# Observation: graph is a DAG, so one needs to go in front of the other. We can do this in three
# steps:
# svr → closest(dac, fft) -> furthest(dac,fft)
rank = {
node: rank
for rank, node in enumerate(nx.topological_sort(graph))
}
rev_rank = {rank: node for node, rank in rank.items()}
if rank["dac"] > rank["fft"]:
closest = "fft"
furthest = "dac"
else:
closest = "dac"
furthest = "fft"
def ranked_all_paths(source: str, dest: str) -> int:
counts = defaultdict(int)
counts[dest] = 1
for r in range(rank[dest], rank[source], -1):
node = rev_rank[r]
if node not in counts:
continue
for u, _ in graph.in_edges(node):
counts[u] += counts[node]
return counts[source]
assert nx.has_path(graph, closest, furthest)
print("Part 1", ranked_all_paths("you", "out"))
first = ranked_all_paths("svr", closest)
second = ranked_all_paths(closest, furthest)
third = ranked_all_paths(furthest, "out")
print("Part 2:", first * second * third)
if __name__ == "__main__":
main()