Rewrite example to show potential deadlock

The example originally showed a certain deadlock, which was not as clear
as it could be. The new version shows intentionally racy code that may
result in a successful execution but may also deadlock.

examples/mutex_cycle.rs

@@ -1,26 +1,62 @@
 //! Show what a crash looks like
 //!
-//! This shows what a traceback of a cycle detection looks like. It is expected to crash.
+//! This shows what a traceback of a cycle detection looks like. It is expected to crash when run in
+//! debug mode, because it might deadlock. In release mode, no tracing is used and the program may
+//! do any of the following:
+//!
+//! - Return a random valuation of `a`, `b`, and `c`. The implementation has a race-condition by
+//!   design. I have observed (4, 3, 6), but also (6, 3, 5).
+//! - Deadlock forever.
+//!
+//! One can increase the SLEEP_TIME constant to increase the likelihood of a deadlock to occur. On
+//! my machine, 1ns of sleep time gives about a 50/50 chance of the program deadlocking.
+use std::thread;
+use std::time::Duration;
+
 use tracing_mutex::stdsync::Mutex;
 
 fn main() {
-    let a = Mutex::new(());
-    let b = Mutex::new(());
-    let c = Mutex::new(());
+    let a = Mutex::new(1);
+    let b = Mutex::new(2);
+    let c = Mutex::new(3);
 
+    // Increase this time to increase the likelihood of a deadlock.
+    const SLEEP_TIME: Duration = Duration::from_nanos(1);
+
+    // Depending on random CPU performance, this section may deadlock, or may return a result. With
+    // tracing enabled, the potential deadlock is always detected and a backtrace should be
+    // produced.
+    thread::scope(|s| {
         // Create an edge from a to b
-    {
-        let _a = a.lock();
-        let _b = b.lock();
-    }
+        s.spawn(|| {
+            let a = a.lock().unwrap();
+            thread::sleep(SLEEP_TIME);
+            *b.lock().unwrap() += *a;
+        });
 
         // Create an edge from b to c
-    {
-        let _b = b.lock();
-        let _c = c.lock();
-    }
+        s.spawn(|| {
+            let b = b.lock().unwrap();
+            thread::sleep(SLEEP_TIME);
+            *c.lock().unwrap() += *b;
+        });
 
-    // Now crash by trying to add an edge from c to a
-    let _c = c.lock();
-    let _a = a.lock(); // This line will crash
+        // Create an edge from c to a
+        //
+        // N.B. the program can crash on any of the three edges, as there is no guarantee which
+        // thread will execute first. Nevertheless, any one of them is guaranteed to panic with
+        // tracing enabled.
+        s.spawn(|| {
+            let c = c.lock().unwrap();
+            thread::sleep(SLEEP_TIME);
+            *a.lock().unwrap() += *c;
+        });
+    });
+
+    println!(
+        "{}, {}, {}",
+        a.into_inner().unwrap(),
+        b.into_inner().unwrap(),
+        c.into_inner().unwrap()
+    );
 }